JEE Advanced levelSingle correct optionDifficulty 3 of 3ie203
A sparingly soluble salt AB has Ksp=1.0×10−5. It is dissolved in 0.002MNaA solution (fully dissociated). Solving without neglecting any term, its solubility (in molL−1) is
A2.3×10−3M
B5.0×10−3M
C3.2×10−3M
D1.2×10−3M
Answer: A
Let solubility be s: s(s+0.002)=1.0×10−5, i.e. s2+0.002s−10−5=0. s=[−0.002+(0.002)2+4×10−5]/2=2.3×10−3M. The shortcut Ksp/0.002 overestimates because s is not small compared with 0.002.