JEE Advanced levelSingle correct optionDifficulty 3 of 3ie200
AgNOX3 is added gradually to a solution containing 0.010MClX− and 0.010MCrOX4X2−. Ksp: AgCl=1.8×10−10, AgX2CrOX4=2.0×10−12. When AgX2CrOX4 just begins to precipitate, [ClX−] left in solution (in molL−1) is
A1.8×10−8M
B1.4×10−5M
C2.0×10−10M
D1.3×10−5M
Answer: D
AgX2CrOX4 begins at [AgX+]=2.0×10−12/0.010=1.4×10−5M. AgCl (which needs only 1.8×10−8MAgX+) has precipitated first, so [ClX−]=1.8×10−10/1.4×10−5=1.3×10−5M.