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JEE Main levelSingle correct optionDifficulty 2 of 3ie069

$40 mL$ of $0.1 M$ $NaOH$ is mixed with $10 mL$ of $0.2 M$ $HCl$ . The pH of the resulting solution is nearest to. Use $lo g 2 = 0.301$ and $lo g 3 = 0.477$ where needed. Take 298 K.

A $12.00$
B $1.40$
C $12.90$
D $12.60$

Answer: D

OH X^{-}

= 4

mmol,

H X^{+}

= 2

mmol, so 2 mmol

OH X^{-}

remain in

50 mL

:

[OH X^{-}] = 0.04 M

.

pOH = 1.398

and

pH = 14 - 1.398 = 12.60

.

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