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JEE Main levelSingle correct optionDifficulty 2 of 3ie068

$50 mL$ of $0.2 M$ $HCl$ is mixed with $50 mL$ of $0.1 M$ $NaOH$ . The pH of the resulting solution is nearest to. Use $lo g 2 = 0.301$ and $lo g 3 = 0.477$ where needed. Take 298 K.

A $1.00$
B $1.30$
C $1.60$
D $7.00$

Answer: B

H X^{+}

= 10

mmol,

OH X^{-}

= 5

mmol, so 5 mmol

H X^{+}

remains in

100 mL

:

[H X^{+}] = 0.05 M

.

pH = - lo g (5 \times 1 0^{- 2}) = 1.301 \approx 1.30

.

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