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JEE Main levelSingle correct optionDifficulty 2 of 3ie067

$100 mL$ of $0.1 M$ $HCl$ is mixed with $100 mL$ of $0.2 M$ $HCl$ . The pH of the mixture is nearest to. Use $lo g 2 = 0.301$ and $lo g 3 = 0.477$ where needed. Take 298 K.

A $0.70$
B $1.18$
C $0.82$
D $0.52$

Answer: C

Total

H X^{+}

= 10 + 20 = 30

mmol in

200 mL

, so

[H X^{+}] = 0.15 M

.

pH = - lo g 0.15 = 0.824 \approx 0.82

.

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