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Ionic Equilibrium II
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Mixtures of weak acids and bases
JEE Main level
Numerical answer
Difficulty 2 of 3
ia191
A solution is
0.10
M
in
CH
X
3
COOH
(
K
a
=
1.8
×
1
0
−
5
) and
0.10
M
in
HCOOH
(
K
a
=
1.8
×
1
0
−
4
). Using
[
H
X
+
]
=
K
1
C
1
+
K
2
C
2
, find the pH (two decimals).
Numerical answer type, tolerance 0.01.
Answer: 2.351667
[
H
X
+
]
=
1.8
×
1
0
−
5
×
0.10
+
1.8
×
1
0
−
4
×
0.10
=
1.98
×
1
0
−
5
=
4.45
×
1
0
−
3
M
. So
pH
=
2.35
.
Practice Ionic Equilibrium II
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