A solution contains 0.1 M HA (K_a = 4.0x10^-6) and 0.1 M HB (K_a = 6.0x10^-6). Using [H+] = sqrtK_1C_1 + K_2C_2, the pH is

NEET levelSingle correct optionDifficulty 1 of 3ia176

A solution contains $0.1 M$ $HA$ ( $K_{a} = 4.0 \times 1 0^{- 6}$ ) and $0.1 M$ $HB$ ( $K_{a} = 6.0 \times 1 0^{- 6}$ ). Using $[H X^{+}] = K_{1} C_{1} + K_{2} C_{2}$ , the pH is

[H X^{+}] = 4.0 \times 1 0^{- 6} \times 0.1 + 6.0 \times 1 0^{- 6} \times 0.1 = 1 0^{- 6} = 1 0^{- 3} M

, so

pH = 3.0