$50 mL$ of $0.2 M$ $CH X_{3} COOH$ is mixed with $50 mL$ of $0.1 M$ $NaOH$ . Given $p K_{a}$ of acetic acid $= 4.74$ , the pH of the mixture is

Answer: D

Acid

= 10 mmol

, base

= 5 mmol

, so

5 mmol

CH X_{3} COOH

and

5 mmol

CH X_{3} COO X^{-}

remain.

pH = p K_{a} + lo g (1) = 4.74

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