JEE Advanced levelNumerical answerDifficulty 3 of 3ig211
20mL of a mixture of CO and HX2 was exploded with 25mL of OX2. After cooling to room temperature the residual gas measured 27mL. The volume of CO in mL (nearest integer) in the original mixture was
Numerical answer type, answer in mL, tolerance 0.5.
Answer: 12 mL
Let CO=a, HX2=20−a. OX2 used =a/2+(20−a)/2=10mL for any a, leaving 15mL. Residual =COX2+OX2=a+15=27, so a=12mL.