$10 mL$ of a gaseous compound containing only C, H and O was burnt in $45 mL$ of $O X_{2}$ (excess). After cooling the volume was $35 mL$ , and after KOH it was $15 mL$ (pure $O X_{2}$ ). The compound is known to have molar mass $46$ . Which statements are correct?

Answer: A, B, C, D

CO X_{2}

= 35 - 15 = 20

, so

x = 2

(A).

O X_{2}

used

= 45 - 15 = 30

(B).

C X_{2} H X_{y} O X_{z} + (2 + \frac{y}{4} - \frac{z}{2}) O X_{2}

10 (2 + y /4 - z /2) = 30

, so

y /4 - z /2 = 1

. With

M = 46

24 + y + 16 z = 46

y + 16 z = 22

z = 1

gives

y = 6

and

6/4 - 1/2 = 1

, consistent.

C X_{2} H X_{6} O

, ethanol (C, D). All correct.