The volume in litres (two decimals) occupied by 11 g of CO2 (molar mass 44) at 273 K and 1.0 atm, taking R = 0.0821 L atm K^-1 mol^-1, is

JEE Main levelNumerical answerDifficulty 2 of 3ig139

The volume in litres (two decimals) occupied by $11 g$ of $CO X_{2}$ (molar mass 44) at $273 K$ and $1.0 atm$ , taking $R = 0.0821 L atm K^{- 1} mo l^{- 1}$ , is

Numerical answer type, answer in L, tolerance 0.02.

n = 11/44 = 0.25 mol

V = \frac{n RT}{P} = 0.25 \times 0.0821 \times 273 = 5.6033 \approx 5.60 L