MolSynapsequestion bank

MolSynapse / Question bank / Gaseous State: Ideal Gases / Gas laws and ideal gas equation

JEE Main levelSingle correct optionDifficulty 2 of 3ig129

A gas cylinder can withstand a maximum pressure of $15 atm$ . It contains gas at $300 K$ and $12 atm$ . The temperature in $^{\circ} C$ at which the cylinder will burst is

A $10 2^{\circ} C$
B $37 5^{\circ} C$
C $7 5^{\circ} C$
D $24 0^{\circ} C$

Answer: A

At constant

V

and

n

,

P \propto T

.

T_{2} = 300 \times \frac{15}{12} = 375 K = 10 2^{\circ} C

.

Practice Gaseous State: Ideal Gases More on Gas laws and ideal gas equation

Previous questionNext question

More questions on Gas laws and ideal gas equation