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JEE Main levelSingle correct optionDifficulty 2 of 3ig012

A gas at $2 7^{\circ} C$ and $1 atm$ is heated so that both its pressure and its volume double. The final temperature is

A $10 8^{\circ} C$
B $92 7^{\circ} C$
C $60 0^{\circ} C$
D $32 7^{\circ} C$

Answer: B

Combined gas law:

\frac{P _{1} V _{1}}{T _{1}} = \frac{P _{2} V _{2}}{T _{2}}

. With

P_{2} = 2 P_{1}

and

V_{2} = 2 V_{1}

,

T_{2} = 4 T_{1} = 4 \times 300 = 1200 K = 92 7^{\circ} C

.

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