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NEET levelSingle correct optionDifficulty 1 of 3ig001

A sample of an ideal gas occupies $6.0 L$ at $2.0 atm$ . If the pressure is raised to $3.0 atm$ at constant temperature, the new volume is

A $4.0 L$
B $9.0 L$
C $3.0 L$
D $2.0 L$

Answer: A

Boyle's law at constant

T

and

n

:

P_{1} V_{1} = P_{2} V_{2}

. So

V_{2} = \frac{2.0 \times 6.0}{3.0} = 4.0 L

. Volume falls because pressure rises.

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