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JEE Main levelSingle correct optionDifficulty 2 of 3ig014

The value of the gas constant $R$ in $L atm K^{- 1} mo l^{- 1}$ is obtained from $R = 8.314 J K^{- 1} mo l^{- 1}$ using $1 atm = 101325 Pa$ . The result is closest to

A $0.0821$
B $8.314$
C $1.987$
D $82.1$

Answer: A

1 L atm = 1 0^{- 3} m^{3} \times 101325 Pa = 101.325 J

. So

R = \frac{8.314}{101.325} = 0.0821 L atm K^{- 1} mo l^{- 1}

.

1.987

is

R

in

cal K^{- 1} mo l^{- 1}

.

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