Chlorobenzene labelled with ^14C at the carbon bearing Cl (C-1) is treated with KNH2 in liquid NH3. Which statements are

Question

Chlorobenzene labelled with ^14C at the carbon bearing Cl (C-1) is treated with KNH2 in liquid NH3. Which statements are correct? (Ignore isotope effects.)

Accepted Answer

The aniline obtained is a roughly 1 : 1 mixture of the compound with ^14C at the carbon bearing NH2 and the compound with ^14C at the carbon ortho to it

Accepted Answer

The intermediate is benzyne, in which the two adjacent carbons are equivalent in their reactivity to NH2-

Answer

All the ^14C remains at the carbon bearing NH2 because substitution is a direct displacement

Answer

The reaction goes via a Meisenheimer complex

Chlorobenzene labelled with $^{14} C$ at the carbon bearing $Cl$ (C-1) is treated with $KNH X_{2}$ in liquid $NH X_{3}$ . Which statements are correct? (Ignore isotope effects.)

Answer: C, D

More questions on Reactions of aryl halides

Chlorobenzene labelled with 14C at the carbon bearing Cl (C-1) is treated with KNHX2​ in liquid NHX3​. Which statements are correct? (Ignore isotope effects.)

Answer: C, D

More questions on Reactions of aryl halides

Chlorobenzene labelled with $^{14} C$ at the carbon bearing $Cl$ (C-1) is treated with $KNH X_{2}$ in liquid $NH X_{3}$ . Which statements are correct? (Ignore isotope effects.)