Answer: A, D
The radical shown is the allyl radical, a resonance hybrid of CHX2=CH−CHX2X∙ and X∙X22∙CHX2−CH=CHX2. The spin density sits on the two terminal carbons and the two C-C bonds are equal (bond order 1.5), so statements 1 and 2 are true. The central carbon carries almost no spin density, and resonance makes allyl more stable than a localised primary radical such as n-propyl.