Answer: B
The hydrocarbon shown is propene; loss of a proton from its methyl group gives the allyl anion, whose negative charge is delocalised over two terminal carbons by resonance. The ethyl, n-propyl and isopropyl anions are localised sp3 carbanions, and alkyl groups destabilise a carbanion through their electron-donating effect, so the allyl anion is the most stable.