A bromine atom abstracts one hydrogen atom from the compound shown. Which radical shown is formed preferentially?

The compound shown is toluene. Abstraction from the methyl group gives the benzyl radical, whose unpaired electron is delocalised over the ring by resonance. Aryl radicals (o-, m- and p-tolyl) have the electron in an sp${}^2$ orbital in the plane of the ring and cannot be delocalised, so the benzyl radical is by far the most stable.