Answer: B, C, D
The cation shown is the neopentyl cation. Its neighbouring carbon is quaternary, so no 1,2-hydride shift is available (statement D true). A 1,2-methyl shift gives the tertiary 2-methylbutan-2-yl cation (statement B true), which is more stable, not less, than the primary cation (statement A false). Deprotonation of the tertiary cation at a CH3 or at the CH2 gives 2-methylbut-1-ene or 2-methylbut-2-ene (statement C true).