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JEE Main levelSingle correct optionDifficulty 2 of 3g3192

A forward step has $E_{a} = 45 kJ mo l^{- 1}$ and $Δ H = - 30 kJ mo l^{- 1}$ . The activation energy of the reverse step is

A75 $kJ mo l^{- 1}$
B45 $kJ mo l^{- 1}$
C30 $kJ mo l^{- 1}$
D15 $kJ mo l^{- 1}$

Answer: A

Δ H = E_{a, fwd} - E_{a, rev}

, so

E_{a, rev} = 45 - (- 30) = 75 kJ mo l^{- 1}

.

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