The reaction C6H5OH + CH3COO- C6H5O- + CH3COOH is considered with pK_a(C6H5OH) = 10.0 and pK_a(CH3COOH) = 4.76. Which statements are correct?

K for the reaction as written is about 5.8 x 10^-6.

The reverse reaction C6H5O- + CH3COOH -> C6H5OH + CH3COO- has K approx 1.7 x 10^5.

Dissolving sodium acetate in phenol gives only a negligible concentration of phenoxide.

K for the reaction as written is about 5.8 x 10^-6.

The reverse reaction C6H5O- + CH3COOH -> C6H5OH + CH3COO- has K approx 1.7 x 10^5.

Dissolving sodium acetate in phenol gives only a negligible concentration of phenoxide.

Acetate ion is a stronger base than phenoxide ion.

JEE Advanced levelOne or more correct optionsDifficulty 3 of 3g2135

The reaction $C X_{6} H X_{5} OH + CH X_{3} COO X^{-} C X_{6} H X_{5} O X^{-} + CH X_{3} COOH$ is considered with $p K_{a} (C X_{6} H X_{5} OH) = 10.0$ and $p K_{a} (CH X_{3} COOH) = 4.76$ . Which statements are correct?

A $K$ for the reaction as written is about $5.8 \times 1 0^{- 6}$ .
BThe reverse reaction $C X_{6} H X_{5} O X^{-} + CH X_{3} COOH C X_{6} H X_{5} OH + CH X_{3} COO X^{-}$ has $K \approx 1.7 \times 1 0^{5}$ .
CDissolving sodium acetate in phenol gives only a negligible concentration of phenoxide.
DAcetate ion is a stronger base than phenoxide ion.

lo g K = 4.76 - 10.0 = - 5.24

, so

K = 5.8 e - 06 \approx 5.8 \times 1 0^{- 6}

(A true). The reverse has

K = 1.74 e + 05 \approx 1.7 \times 1 0^{5}

(B true). Because

K

is tiny, little phenoxide forms (C true). Acetate is the conjugate base of the stronger acid and is therefore the weaker base (D false).