Answer: C
COX2 in water behaves as HX2COX3 (6.4). It protonates phenoxide because phenol (10.0) is a weaker acid (logK=10.0−6.4=3.6>0) and gives phenol and bicarbonate. Benzoate is the conjugate base of a stronger acid (4.20), so logK=4.20−6.4=−2.2 and no benzoic acid is formed.