Numerical answer type, tolerance 0.5.
Answer: 7
Protonation of one sp2 carbon gives the tertiary cation (CHX3)X2CH−CX+(CHX3)X2 (the alkene is symmetric, so there is only one choice). The cationic carbon bears two CHX3 groups (2×3=6 alpha H) and one CH(CHX3)X2 group whose methine carbon has 1 alpha H. Total 6+1=7.