JEE Main levelNumerical answerDifficulty 2 of 3eq192
A 0.4250g sample containing sodium oxalate (NaX2CX2OX4, molar mass 134) and inert matter is dissolved, acidified and titrated at 60−70∘C with 0.0200MKMnOX4; 24.30mL is required. Find the percentage of NaX2CX2OX4 in the sample (two decimals).
Numerical answer type, answer in %, tolerance 0.05.
Answer: 38.31 %
Mmol of KMnOX4=24.30×0.0200=0.486; oxalate =0.486×5/2=1.215 mmol. Mass =1.215×134=162.8 mg. Percentage =162.8/425.0×100=38.31%.