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JEE Main levelSingle correct optionDifficulty 2 of 3eq189

Volume of $0.100 M$ oxalic acid that reacts completely with $10.0 mL$ of $0.0500 M$ acidified $KMnO X_{4}$ is:

A $5.0 mL$
B $25.0 mL$
C $12.5 mL$
D $2.5 mL$

Answer: C

Meq of

KMnO X_{4}

= 10.0 \times 0.0500 \times 5 = 2.50

. Oxalic acid

0.100 M

is

0.200 N

(n = 2). Volume

= 2.50/0.200 = 12.5 mL

.

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