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JEE Main levelSingle correct optionDifficulty 2 of 3eq177

A '20 volume' $H X_{2} O X_{2}$ solution gives $20 mL$ of $O X_{2}$ at STP per $mL$ of solution on decomposition (molar volume $22.4 L mo l^{- 1}$ ). Its normality, taking n-factor of $H X_{2} O X_{2}$ as 2, is:

A $7.14 N$
B $1.79 N$
C $0.89 N$
D $3.57 N$

Answer: D

2 H X_{2} O X_{2} \to 2 H X_{2} O + O X_{2}

, so

1 L

gives

20 L

of

O X_{2}

= 20/22.4 = 0.893

mol, and

H X_{2} O X_{2}

= 1.786 M

. Normality

= 2 \times 1.786 = 3.57 N

(equivalently

20/5.6

).

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