27.5 mL of 0.0360 M KMnO4 in acidic medium is exactly equivalent to what volume (in mL) of 0.0850 M oxalic acid (H2C2O4, oxidised to CO2)? Give the answer to one decimal place.

JEE Main levelNumerical answerDifficulty 2 of 3eq174

$27.5 mL$ of $0.0360 M$ $KMnO X_{4}$ in acidic medium is exactly equivalent to what volume (in $mL$ ) of $0.0850 M$ oxalic acid ( $H X_{2} C X_{2} O X_{4}$ , oxidised to $CO X_{2}$ )? Give the answer to one decimal place.

Numerical answer type, answer in mL, tolerance 0.1.

Equivalents of

KMnO X_{4}

= 27.5 \times 0.0360 \times 5 = 4.950

meq. Normality of oxalic acid

= 2 \times 0.0850 = 0.170 N

. Volume

= 4.950/0.170 = 29.12 mL