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JEE Main levelNumerical answerDifficulty 2 of 3eq178

$150 mL$ of $0.12 M$ $H X_{2} SO X_{4}$ is mixed with $350 mL$ of $0.10 M$ $HCl$ . Find the normality of the resulting solution as an acid (two decimals).

Numerical answer type, answer in N, tolerance 0.01.

Answer: 0.14 N

Milliequivalents

= 150 \times 0.12 \times 2 + 350 \times 0.10 \times 1 = 36 + 35 = 71

. Normality

= 71/500 = 0.142 N

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