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JEE Main levelSingle correct optionDifficulty 2 of 3eq172

$6.3 g$ of oxalic acid dihydrate, $H X_{2} C X_{2} O X_{4} \cdot 2 H X_{2} O$ (molar mass $126 g mo l^{- 1}$ ), is dissolved in water to make $500 mL$ of solution. Its normality when used as a reducing agent (oxidised to $CO X_{2}$ ) is:

A $0.40 N$
B $0.10 N$
C $0.05 N$
D $0.20 N$

Answer: D

Moles

= 6.3/126 = 0.05

; equivalents

= 0.05 \times 2 = 0.10

. Normality

= 0.10/0.500 = 0.20 N

.

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