JEE Main levelSingle correct optionDifficulty 2 of 3eq099
A 0.800g antacid tablet containing Mg(OH)X2 (molar mass 58) is dissolved in 50.0mL of 0.200MHCl. The excess acid needs 20.0mL of 0.150MNaOH. Assuming no other base is present, the mass percent of Mg(OH)X2 is
A50.8%
B36.3%
C25.4%
D12.7%
Answer: C
HCl taken = 0.0100 mol; excess = 0.0200 x 0.150 = 0.0030 mol; consumed = 0.0070 mol. Mg(OH)2 neutralises 2 H+, so mol = 0.0035, mass = 0.2030 g. Percent = 0.2030/0.800 x 100 = 25.38%.