Acidified 0.020 M KMnO4 is used to oxidise 0.10 mol of FeSO4 to Fe^3+. The volume of permanganate solution required is

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Acidified $0.020 M$ $KMnO X_{4}$ is used to oxidise $0.10$ mol of $FeSO X_{4}$ to $Fe X^{3 +}$ . The volume of permanganate solution required is

Equivalents of Fe2+ = 0.10 x 1 = 0.10. Normality of KMnO4 = 0.020 x 5 = 0.10 N. Volume = 0.10 eq / 0.10 eq/L = 1.0 L.