MolSynapse
question bank
All chapters
NEET
JEE
Practice
MolSynapse
/
Question bank
/
Equivalent Concept and Titration
/
n-factor for oxidants and reductants, normality
JEE Main level
Single correct option
Difficulty 2 of 3
eq029
20.0
mL
of
0.100
M
FeSO
X
4
is titrated in acidic medium with
0.0200
M
K
X
2
Cr
X
2
O
X
7
(
Cr
X
2
O
X
7
X
2
−
Cr
X
3
+
). The volume of dichromate needed is:
A
100 mL
B
16.7 mL
C
33.3 mL
D
20.0 mL
Answer: B
Equivalents of
FeSO
X
4
=
0.100
×
0.0200
=
2.00
×
1
0
−
3
(
n
=
1
). Dichromate normality
=
0.0200
×
6
=
0.120
N
. Volume
=
2.00
×
1
0
−
3
/0.120
=
0.01667
L
=
16.7
mL
.
Practice Equivalent Concept and Titration
More on n-factor for oxidants and reductants, normality
Previous question
Next question
More questions on n-factor for oxidants and reductants, normality
The strength of a H2O2 solution is 20 volume, i.e. 1 mL of the solution gives 20 mL of O2 at STP on decomposition (2H2O2 -> 2H2O + O2; molar...
JEE Main level
FeC2O4 (molar mass 144 g mol^-1) is oxidised completely by acidified KMnO4 to Fe^3+ and CO2. Its equivalent mass is:
JEE Main level
Select the correct n-factor(s) per formula unit of the species named, for the stated change.
JEE Main level
Mohr's salt, FeSO4.(NH4)2SO4.6H2O, is titrated with acidified KMnO4. Using Fe=56, S=32, N=14, O=16, H=1, its equivalent mass is:
JEE Main level
Bromine disproportionates in hot alkali: 3Br2 + 6OH- -> 5Br- + BrO3- + 3H2O (Br=80). The equivalent mass of Br2 in this reaction is:
JEE Advanced level
Cu2S (Cu=63.5, S=32) is oxidised by acidified KMnO4 to Cu^2+ and SO2. Calculate the mass of KMnO4 (molar mass 158 g mol^-1) required to oxid...
JEE Advanced level