JEE Main levelSingle correct optionDifficulty 2 of 3eq026
The strength of a HX2OX2 solution is 20 volume, i.e. 1mL of the solution gives 20mL of OX2 at STP on decomposition (2HX2OX22HX2O+OX2; molar volume 22.4L at STP). Its normality as an oxidant or reductant (n=2) is:
A1.79 N
B7.14 N
C0.89 N
D3.57 N
Answer: D
1L gives 20LOX2=20/22.4=0.893 mol, and 2 mol HX2OX2 are used per mol OX2, so [HX2OX2]=1.786M. With n=2, N=3.57N (equivalently 20/5.6).