Mohr's salt, FeSO4.(NH4)2SO4.6H2O, is titrated with acidified KMnO4. Using Fe=56, S=32, N=14, O=16, H=1, its equivalent mass is:

JEE Main levelSingle correct optionDifficulty 2 of 3eq030

Mohr's salt, $FeSO X_{4} \cdot (NH X_{4}) X_{2} SO X_{4} \cdot 6 H X_{2} O$ , is titrated with acidified $KMnO X_{4}$ . Using $Fe = 56$ , $S = 32$ , $N = 14$ , $O = 16$ , $H = 1$ , its equivalent mass is:

Molar mass

= 56 + 32 + 64 + 2 (14 + 4) + 32 + 64 + 6 \times 18 = 392

. Only

Fe X^{2 +} Fe X^{3 +}

is oxidised (

n = 1

), so equivalent mass

= 392/1 = 392