The equivalent masses of $KMnO X_{4}$ (molar mass $158 g mo l^{- 1}$ ) as an oxidant in acidic, neutral and strongly alkaline medium respectively are:

Answer: C

Acidic:

MnO X_{4} X^{-} Mn X^{2 +}

n = 5

158/5 = 31.6

. Neutral:

MnO X_{4} X^{-} MnO X_{2}

n = 3

158/3 = 52.7

. Strongly alkaline:

MnO X_{4} X^{-} MnO X_{4} X^{2 -}

n = 1

158

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