For complete reaction with excess aqueous $HCl$ , the equivalent mass equals half of the molar mass for which of the following?

Answer: A, C

Equivalent mass

=

molar mass

/ n

, so we need

n = 2

Na X_{2} CO X_{3}

takes 2

H X^{+}

(

n = 2

) and

Ca (OH) X_{2}

supplies 2

OH X^{-}

(

n = 2

NaHCO X_{3}

has

n = 1

and

Al (OH) X_{3}

has

n = 3

3.7 g of Ca(OH)2 (molar mass 74 g mol^-1) is dissolved in water to make 250 mL of solution. Its normality for complete neutralisation by an ... JEE Main level
A sulfuric acid solution is 30% H2SO4 by mass and has density 1.22 g mL^-1 (molar mass of H2SO4 =98 g mol^-1). Its normality (for complete n... JEE Main level
Select the correct statement(s) about n-factors in the stated acid-base reactions. JEE Main level
Na2CO3 (molar mass 106 g mol^-1) is titrated with HCl and the titration is stopped at the phenolphthalein end point, where only CO3^2- -> HC... JEE Main level
17.1 g of Al2(SO4)3 (molar mass 342 g mol^-1) is completely precipitated as BaSO4 by BaCl2 solution (treat BaCl2 as having n=2). Select the ... JEE Main level
A 2.90 g mixture of NaOH and Ca(OH)2 (molar masses 40 and 74 g mol^-1) is exactly neutralised by 75.5 mL of 1.00 N HCl. Calculate the mass p... JEE Advanced level