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JEE Main levelSingle correct optionDifficulty 2 of 3eq007

$3.7 g$ of $Ca (OH) X_{2}$ (molar mass $74 g mo l^{- 1}$ ) is dissolved in water to make $250 mL$ of solution. Its normality for complete neutralisation by an acid is:

A0.2 N
B0.8 N
C0.1 N
D0.4 N

Answer: D

Equivalent mass

= 74/2 = 37

, so equivalents

= 3.7/37 = 0.1

. Normality

= 0.1/0.25 L = 0.4 N

(molarity is

0.2 M

, and

N = M \times n = 0.4

).

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