Organic waste in a sanitary landfill decomposes anaerobically. Treat the waste as glucose which converts completely by C6H12O6 -> 3CH4 + 3CO2. Use C 12, H 1, O 16 and molar volume 22.4 L/mol at STP. The volume of methane at STP from 1.80 kg of glucose is

JEE Advanced levelSingle correct optionDifficulty 3 of 3ev212

Organic waste in a sanitary landfill decomposes anaerobically. Treat the waste as glucose which converts completely by $C X_{6} H X_{12} O X_{6} 3 CH X_{4} + 3 CO X_{2}$ . Use C 12, H 1, O 16 and molar volume 22.4 L/mol at STP. The volume of methane at STP from 1.80 kg of glucose is

Moles of glucose

= 1800/180 = 10

. The equation is balanced (6 C, 12 H, 6 O on each side) and gives 3 mol of methane per mol, so 30 mol. Volume

= 30 \times 22.4 = 672