Ethanol is made by two routes. Route A: C2H5Br + NaOH - C2H5OH + NaBr, yield 90%. Route B: C2H4 + H2O - C2H5OH, yield

Question

Ethanol is made by two routes. Route A: C2H5Br + NaOH -> C2H5OH + NaBr, yield 90%. Route B: C2H4 + H2O -> C2H5OH, yield 60%. Use atomic masses H 1, C 12, O 16, Na 23, Br 80. Which statement is correct?

Accepted Answer

Route B has the higher atom economy, but route A gives more ethanol per mole of limiting reactant

Answer

Route A has the higher atom economy and gives more ethanol per mole of limiting reactant

Answer

Route B has the higher atom economy and also gives more ethanol per mole of limiting reactant

Answer

Route A has the higher atom economy, but route B gives more ethanol per mole of limiting reactant

Ethanol is made by two routes. Route A: $C X_{2} H X_{5} Br + NaOH C X_{2} H X_{5} OH + NaBr$ , yield 90%. Route B: $C X_{2} H X_{4} + H X_{2} O C X_{2} H X_{5} OH$ , yield 60%. Use atomic masses H 1, C 12, O 16, Na 23, Br 80. Which statement is correct?

Answer: A

More questions on Green chemistry and waste management

Ethanol is made by two routes. Route A: CX2​HX5​Br+NaOH​CX2​HX5​OH+NaBr, yield 90%. Route B: CX2​HX4​+HX2​O​CX2​HX5​OH, yield 60%. Use atomic masses H 1, C 12, O 16, Na 23, Br 80. Which statement is correct?

Answer: A

More questions on Green chemistry and waste management

Ethanol is made by two routes. Route A: $C X_{2} H X_{5} Br + NaOH C X_{2} H X_{5} OH + NaBr$ , yield 90%. Route B: $C X_{2} H X_{4} + H X_{2} O C X_{2} H X_{5} OH$ , yield 60%. Use atomic masses H 1, C 12, O 16, Na 23, Br 80. Which statement is correct?