Nernst equation

15 questions on Nernst equation from the Electrochemistry chapter: 2 NEET level, 8 JEE Main, 5 JEE Advanced. Each one opens with its answer and solution.

• For the cell Pt | H2 (1 bar) | HCl (m) | AgCl(s) | Ag, treating activities as molalities, a ten-fold increase in m changes the cell EMF by JEE Advanced level
• Using K_w = 10^-14 at 298 K, the standard potential of the half reaction 2H2O + 2e- -> H2 + 2OH- is closest to JEE Main level
• E deg(Fe^3+/Fe^2+) = 0.77 V. The reduction potential of a platinum electrode dipped in a solution with [Fe^3+] = 0.1 M and [Fe^2+] = 1.0 M at 298 K is (take 2.3... NEET level
• For a metal electrode M^2+/M at 298 K, the electrode potential is plotted against log[M^2+]. The slope of the straight line obtained is (take 2.303RT/F = 0.0591... NEET level
• For the cell Al | Al^3+ (0.01 M) || Sn^2+ (0.1 M) | Sn at 298 K, E deg(Al^3+/Al) = -1.66 V and E deg(Sn^2+/Sn) = -0.14 V. The cell EMF in mV is (nearest integer... JEE Main level
• A Daniell cell Zn | Zn^2+ (1.0 M) || Cu^2+ (0.02 M) | Cu is operated at 350 K. Assume E deg_cell = 1.10 V does not change with temperature. Take R = 8.314 J mol... JEE Advanced level
• E deg(Cl2/Cl-) = 1.36 V. The reduction potential of a chlorine electrode at 298 K with p_Cl2 = 0.1 bar and [Cl-] = 0.2 M is (take 2.303RT/F = 0.0591 V, log 2.5 ... JEE Main level
• A Daniell cell Zn | Zn^2+ || Cu^2+ | Cu is working at 298 K. Which of the following changes will INCREASE the cell EMF? JEE Advanced level
• The cell Pt | H2 (1 bar) | H+ (1 M) || Cu^2+ (x M) | Cu shows an EMF of 0.290 V at 298 K. Given E deg(Cu^2+/Cu) = 0.34 V and 2.303RT/F = 0.0591 V, the value of ... JEE Advanced level
• For two divalent metals M and N, the cell M | M^2+ (0.01 M) || N^2+ (0.1 M) | N has EMF 0.443 V at 298 K. The value of log_10 K for the reaction M + N^2+ -> M^2... JEE Advanced level
• The reduction potential of the hydrogen electrode Pt | H2 (4 bar) | H+ in a solution of pH 4 at 298 K is (take 2.303RT/F = 0.0591 V, log 2 = 0.301) JEE Main level
• A Daniell cell with E deg_cell = 1.10 V is allowed to discharge at 298 K until its EMF falls to zero. At that point the ratio [Zn^2+]/[Cu^2+] is (take 2.303RT/F... JEE Main level
• E deg(MnO4^-, H+/Mn^2+) = 1.51 V. The reduction potential at 298 K when [MnO4^-] = [Mn^2+] = 1 M and pH = 1 is (in V, two decimals). Take (2.303RT)/(F) = 0.0591... JEE Main level
• Excess aqueous ammonia is added to the Cu^2+ compartment of a working Daniell cell. The cell EMF JEE Main level
• For Zn | Zn^2+ (0.1 M) || Cu^2+ (0.01 M) | Cu with E deg_cell = 1.10 V, the EMF at 298 K is closest to JEE Main level