Given Lambda deg_m (in S cm^2 mol^-1): BaCl2 = 280, NaCl = 126.5, Na2SO4 = 260. The limiting molar conductivity of BaSO4 is

JEE Main levelSingle correct optionDifficulty 2 of 3ec23

Given $Λ_{m}^{\circ}$ (in $S c m^{2} mo l^{- 1}$ ): $BaCl X_{2} = 280$ , $NaCl = 126.5$ , $Na X_{2} SO X_{4} = 260$ . The limiting molar conductivity of $BaSO X_{4}$ is

Kohlrausch:

Λ^{\circ} (BaSO X_{4}) = Λ^{\circ} (BaCl X_{2}) + Λ^{\circ} (Na X_{2} SO X_{4}) - 2 Λ^{\circ} (NaCl) = 280 + 260 - 253 = 287

. Two NaCl are subtracted because

2 Na X^{+}

and

2 Cl X^{-}

must be removed.