JEE Advanced levelNumerical answerDifficulty 2 of 3ec24
The conductivity of a saturated BaSOX4 solution, after subtracting that of water, is 2.87×10−6Scm−1. Taking Λm∘(BaSOX4)=287Scm2mol−1, the solubility of BaSOX4 in molL−1 is y×10−5. The value of y (one decimal) is.
Numerical answer type, tolerance 0.05.
Answer: 1
For a sparingly soluble salt Λm≈Λm∘. c=Λm∘1000κ=2871000×2.87×10−6=1.0×10−5molL−1. (Ksp=c2=10−10.)