Answer: A, B, C
λ∘(KX+)=t+Λ∘(KCl)=0.4907×149.8=73.5, so (A) is correct, and λ∘(ClX−)=149.8−73.5=76.3 Scm2mol−1. By Kohlrausch's law λ∘(KX+) is the same in KNOX3, so λ∘(NOX3X−)=144.9−73.5=71.4 and (B) is correct. t(KX+) in KNOX3=73.5/144.9=0.507, so (C) is correct. Since u=λ∘/F and 71.4<76.3, NOX3X− is less mobile than ClX−, so (D) is wrong.