Limiting molar conductivities (in S cm^2 mol^-1) are: NH4Cl = 149.7, NaOH = 248.1, NaCl = 126.4. The limiting molar conductivity of NH4OH is

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Limiting molar conductivities (in $S c m^{2} mo l^{- 1}$ ) are: $NH X_{4} Cl = 149.7$ , $NaOH = 248.1$ , $NaCl = 126.4$ . The limiting molar conductivity of $NH X_{4} OH$ is

Λ^{\circ} (NH X_{4} OH) = λ^{\circ} (NH X_{4} X^{+}) + λ^{\circ} (OH X^{-}) = Λ^{\circ} (NH X_{4} Cl) + Λ^{\circ} (NaOH) - Λ^{\circ} (NaCl)

= 149.7 + 248.1 - 126.4 = 271.4 S c m^{2} mo l^{- 1}

. Subtracting NaOH instead of NaCl gives the wrong value

28.0