Answer: A, C, D
n=2 per mole of HX2, so E∘=237100/(2×96500)=1.23 V; (A) correct. Efficiency =ΔrG∘/ΔrH∘=237.1/285.8=0.83; (C) correct. ΔrS∘=(ΔrH∘−ΔrG∘)/T=(−285.8+237.1)×103/298=−163 JK−1mol−1; (D) correct. At 0.70 V the electrical work is 2×96500×0.70=135.1 kJ and the heat released is 285.8−135.1=150.7 kJ, not 102 kJ (which is 237.1−135.1); (B) wrong.