Answer: B, C, D
Carbon goes from −4 in CHX4 to +4 in COX2, so n=8; (B) correct. E∘=−ΔrG∘/(nF)=818000/(8×96500)=1.06 V; (C) correct. Efficiency =818/890=0.919≈92%; (D) correct. One mole of methane needs 8×96500=772000 C, which at 1.00 A takes 772000 s=214 h; 26.8 h corresponds to one Faraday only, so (A) is wrong.