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JEE Advanced levelSingle correct optionDifficulty 3 of 3df145

Aqueous reacts with to give the dark blue pigment Turnbull's blue, which is the same as Prussian blue, . In this solid the carbon-bonded Fe is low-spin Fe(II) and the nitrogen-bonded Fe is high-spin Fe(III). The colour of the pigment and the spin-only magnetic moment per formula unit are respectively:

  1. Aintervalence charge transfer; 1.73 BM
  2. Bligand-to-metal charge transfer; 0 BM
  3. Cd-d transition; 5.92 BM
  4. Dintervalence (metal-to-metal) charge transfer; 5.92 BM

Answer: D

Low-spin Fe(II) in the -bonded site has , with no unpaired electron. High-spin Fe(III) is with , giving . The intense colour comes from electron transfer between the two iron sites.
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