JEE Advanced levelSingle correct optionDifficulty 3 of 3df144
Green aqueous KX2MnOX4 is acidified and disproportionates: 3MnOX4X2−+4HX+2MnOX4X−+MnOX2+2HX2O. The purple product in the solution is best described as:
Acoloured by d-d transition and diamagnetic
Bcoloured by ligand-to-metal charge transfer and diamagnetic
Ccoloured by d-d transition and paramagnetic with 1 unpaired electron
Dcoloured by ligand-to-metal charge transfer and paramagnetic with 1 unpaired electron
Answer: B
The equation is balanced (3 Mn, 12 O, 4 H, charge -2 on both sides). The purple product is MnOX4X−, with Mn(VII) 3d0. No d electron means it is diamagnetic and no d-d transition occurs, so its colour is charge transfer.