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JEE Main levelSingle correct optionDifficulty 2 of 3df064

Match the species in Column I with the oxidation state of the metal in Column II. Column I: (P) $VO X_{2} X^{+}$ (Q) $MnO X_{4} X^{2 -}$ (R) $[Fe (CN) X_{6}] X^{3 -}$ (S) $Ni (CO) X_{4}$ Column II: (1) $0$ (2) $+ 3$ (3) $+ 5$ (4) $+ 6$

AP-3, Q-4, R-2, S-1
BP-3, Q-4, R-1, S-2
CP-4, Q-3, R-2, S-1
DP-2, Q-4, R-3, S-1

Answer: A

In

VO X_{2} X^{+}

:

x - 4 = + 1

gives

+ 5

. In

MnO X_{4} X^{2 -}

:

x - 8 = - 2

gives

+ 6

. In

[Fe (CN) X_{6}] X^{3 -}

:

x - 6 = - 3

gives

+ 3

. In

Ni (CO) X_{4}

CO is neutral, so Ni is

0

. Hence P-3, Q-4, R-2, S-1.

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